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4.7 assignment find the values of x and y. (6y - 5)° (10y - 41)° (12x +…

Question

4.7 assignment
find the values of x and y.
(6y - 5)° (10y - 41)°
(12x + 22)°
x=
y=

Explanation:

Step1: Use the property of isosceles triangle

Since the two sides of the triangle are equal, the base - angles are equal. So, \(6y - 5=10y - 41\).

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Step2: Use the angle - sum property of a triangle

The sum of angles in a triangle is \(180^{\circ}\). Substitute \(y = 9\) into the angle expressions: \(6y-5=6\times9 - 5=49^{\circ}\), \(10y - 41=10\times9-41 = 49^{\circ}\). Then \(49+49+(12x + 22)=180\).

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Answer:

\(x = 5\), \(y = 9\)