Question

ashley is the oldest of four siblings whose ages are consecutive even integers. if the sum of their ages is 100, find ashleys age.

Explanation:

Step1: Let the ages

Let the ages of the four siblings be $x - 6$, $x - 4$, $x - 2$, $x$ (since they are consecutive even integers and Ashley is the oldest with age $x$).

Step2: Set up the equation

The sum of their ages is 100, so $(x - 6)+(x - 4)+(x - 2)+x=100$.

Step3: Simplify the left - hand side

Combine like terms: $4x-12 = 100$.

Step4: Solve for $x$

Add 12 to both sides: $4x=100 + 12=112$. Then divide both sides by 4, $x=\frac{112}{4}=28$.

Answer:

28