Question

antoine stands on a balcony and throws a ball to his dog, who is at ground level.
the balls height (in meters above the ground), ( x ) seconds after antoine threw it, is modeled by:
( h(x) = -2x^2 + 4x + 16 )
what is the height of the ball at the time it is thrown?
(\boxed{quad}) meters

Explanation:

Step1: Determine time of throw

The ball is thrown at \( x = 0 \) seconds (initial time).

Step2: Substitute \( x = 0 \) into \( h(x) \)

Substitute \( x = 0 \) into \( h(x)=-2x^{2}+4x + 16 \):
\( h(0)=-2(0)^{2}+4(0)+16 \)
\( h(0)=0 + 0+16=16 \)

Answer:

16