Question

answer attempt 1 out of 2
m∠mnp = \boxed{\space}^\circ m∠onp = \boxed{\space}^\circ
m∠mnp + m∠onp = \boxed{\space}^\circ

Explanation:

Step1: Analyze ∠MNP

∠MNP is a straight angle? Wait, no. Wait, MN and NP: Wait, MN is a line, and NP is a line? Wait, no, looking at the protractor. Wait, ∠MNP: points M, N, P. So MN is a ray, NP is a ray? Wait, no, the straight line is M-N-P? Wait, no, the protractor: the base line is from N to Q (the 0° line), and the other line is NA. Wait, maybe I misread. Wait, ∠MNP: M, N, P. So N is the vertex. MN is a ray going left, NP is a ray? Wait, no, the straight angle: if M, N, P are colinear? Wait, no, the protractor shows that ∠ONP: O, N, P. Wait, maybe the first angle: ∠MNP. Wait, MN is a ray, NP is a straight line? Wait, no, the protractor's 0° is at Q (right), and the other line is NA at 55°? Wait, no, the protractor has markings: 0°, 10°, 20°,... 180°. Wait, ∠MNP: since M, N, P are colinear? Wait, no, maybe ∠MNP is 180° - ∠ONP? Wait, no, let's look again.

Wait, the protractor: the line NQ is at 0° (right), and NA is at 55°? Wait, no, the markings: the numbers go from 0° (right) up to 180° (left). So ∠ONP: O, N, P. O is on NQ (0°), P is... Wait, NQ is the 0° line (right), NA is at 55°? Wait, the protractor's scale: from 0° (right) to 180° (left). So ∠ONP: the angle between NO (0°) and NP? Wait, no, NP is the straight line? Wait, maybe ∠MNP is 180° - 55°? Wait, no, let's see:

Wait, the first angle: m∠MNP. Since M, N, P: if MN is a ray going left, and NP is a ray going right (but that would be 180°), but no. Wait, maybe I made a mistake. Wait, the protractor: the line NA is at 55° (from 0°). So ∠ONP: O, N, A? Wait, no, the problem says ∠ONP. Wait, O is on the 0° line (NQ), N is the vertex, P is... Wait, maybe the angles:

Wait, m∠MNP: since M, N, P are such that MN is a ray, and NP is a ray. Wait, maybe ∠MNP is 180° - 55°? Wait, no, let's check the protractor. The protractor shows that the angle between NA and NQ (0°) is 55°? Wait, the marking on NA is at 55°? Wait, the protractor has 50° and 60°, so maybe 55°? Wait, no, the line NA is between 50° and 60°, maybe 55°? Wait, but ∠MNP: if MN is a straight line (180°) and ∠ONP is 55°, then ∠MNP is 180° - 55° = 125°? Wait, no, maybe not. Wait, let's re-express:

Wait, the problem has three parts: m∠MNP, m∠ONP, and their sum.

First, m∠ONP: O, N, P. O is on the 0° line (NQ), P is... Wait, NA is at 55° (from 0°), so ∠ONP is 55°? Wait, no, maybe ∠ONP is 55°, and ∠MNP is 180° - 55° = 125°, and their sum is 180°.

Yes, that makes sense. Because ∠MNP and ∠ONP are supplementary (they form a linear pair), so their sum is 180°.

So Step1: Find m∠ONP. The protractor shows that the angle between NO (0°) and NA (or NP?) is 55°? Wait, the line NA is at 55° (from 0°), so m∠ONP = 55°.

Step2: Find m∠MNP. Since ∠MNP and ∠ONP are supplementary (they form a linear pair, as M, N, P are colinear? Wait, no, M, N, P: if MN is a ray, and NP is a ray, but actually, M, N, O, P: maybe MN is a straight line, and O is on MN? Wait, maybe N is the vertex, M and P are on a straight line, and O is a point such that ∠ONP is 55°, so ∠MNP is 180° - 55° = 125°.

Step3: Sum of m∠MNP and m∠ONP: 125° + 55° = 180°.

Answer:

m∠MNP = \boxed{125}°, m∠ONP = \boxed{55}°, m∠MNP + m∠ONP = \boxed{180}°

Wait, but let's confirm. The protractor: the angle between the 0° line (NQ) and NA is 55°, so ∠ONP is 55°, and ∠MNP is 180° - 55° = 125°, and their sum is 180°, which is a straight angle. So that makes sense.