Question

1. another soccer team had tryouts for the fall season. this team had 60 players show up for the tryouts and had 9 players return for a second evaluation. what percent of the players at the tryout were asked back for a second evaluation?

part =
whole =
percent =
substitute and solve:
final result:

Explanation:

Step1: Define part, whole, percent

The "part" is the number of players asked back, which is 9. The "whole" is the total number of players at tryouts, which is 60. We need to find the "percent". The formula for percent is $\text{percent} = \frac{\text{part}}{\text{whole}} \times 100\%$.

Step2: Substitute values

Substitute part = 9 and whole = 60 into the formula: $\text{percent} = \frac{9}{60} \times 100\%$.

Step3: Calculate the fraction

Simplify $\frac{9}{60}$ to $\frac{3}{20}$ (by dividing numerator and denominator by 3).

Step4: Multiply by 100%

$\frac{3}{20} \times 100\% = 3 \times 5\% = 15\%$ (since $\frac{100\%}{20}=5\%$).

Answer:

The percent of players asked back is 15%. For the blanks: part = 9, whole = 60, percent = 15% (after substitution and solving, the final result is 15%).