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the amount of money in nadias savings account at the end of \\(n\\) yea…

Question

the amount of money in nadias savings account at the end of \\(n\\) years is represented by the recursive formula \\(a_n = 1.025(a_{n-1}) + 50\\). if \\(a_6 = 291.51\\), what is the balance in nadias account at the end of each of the first two years?

\\$25.36, \\$75.99
\\$50.00, \\$101.25
\\$101.25, \\$153.78
\\$75.99, \\$127.89

Explanation:

Express the recursive relation backwards

$$ LATEXBLOCK0 $$

Calculate preceding terms from \(a_6 = 291.51\)

$$ LATEXBLOCK1 $$

Identify the balances for the first two years

$$ LATEXBLOCK2 $$

Answer:

  • (A) $25.36, $75.99 (Correct answer)
  • (B) $50.00, $101.25
  • (C) $101.25, $153.78
  • (D) $75.99, $127.89