Question

algebra cc name graphing linear equations not in standard form 0 x + y = -1 slope (m): -1 y- intercept (b): -1 table: x y -2 1 -1 0 0 -1 1 -2 2 -3 3 -4 4 -5 5 -6

Explanation:

Step1: Convert to slope - intercept form

The equation given is \(x + y=-1\). We want to write it in the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the \(y\) - intercept.
Subtract \(x\) from both sides of the equation: \(y=-x - 1\).

Step2: Identify slope and \(y\) - intercept

In the slope - intercept form \(y = mx + b\), for the equation \(y=-x - 1\), the coefficient of \(x\) is the slope \(m\) and the constant term is the \(y\) - intercept \(b\).
So, \(m=-1\) and \(b = - 1\).

Step3: Verify with the table

Let's take a value of \(x\) from the table, say \(x = 0\). Substitute into \(y=-x - 1\), we get \(y=-0 - 1=-1\), which matches the table.
For \(x = 1\), \(y=-1-1=-2\), which also matches the table. This confirms that the slope and \(y\) - intercept are correct.

Answer:

Slope (\(m\)): \(-1\), \(y\) - intercept (\(b\)): \(-1\)