Question

algebra 2a semester online practice
complete this assessment to review what youve learned. it will not count toward your grade.

what is the point of inflection of the new function obtained by shifting the function, ( g(x) = x^3 - 15 ), 4 units upwards from the inflection point of ( g(x) )? (1 point)

( circ (0, -19) )

( circ (11, 0) )

( circ (-11, 0) )

( circ (0, -11) )

Explanation:

Step1: Find inflection point of \( g(x) \)

For \( g(x) = x^3 - 15 \), the inflection point of \( y = x^3 \) is \( (0,0) \). Shifting down 15, \( g(x) \)’s inflection point is \( (0, -15) \).

Step2: Shift inflection point up 4 units

To shift \( (0, -15) \) 4 units up, add 4 to the y - coordinate: \( -15 + 4 = -11 \). So the new inflection point is \( (0, -11) \).

Answer:

\( (0, -11) \)