Question

an airplane takes off 600 feet in front of a 60 foot building. at what angle of elevation must the plane take off in order to avoid crashing into the building? assume that the airplane flies in a straight line and the angle of elevation remains constant until the airplane flies over the building. about 6 degrees i love math! about.1 degree about 84 degrees

Explanation:

Step1: Identify right triangle sides

Opposite side = 60 ft, adjacent side = 600 ft

Step2: Use tangent function

$\tan(\theta) = \frac{60}{600} = 0.1$

Step3: Calculate angle

$\theta = \arctan(0.1) \approx 5.71^\circ \approx 6^\circ$

Answer:

about 6 degrees