Question

the age, in years, of 10 randomly selected passengers on a flight from houston to new orleans were recorded as \\{23, 48, 52, 34, 22, 53, 19, 23, 32, 27\\}. calculate the sample mean age to the nearest integer. (1 point) 25 years 34 years 21 years 333 years

Explanation:

Step1: Sum all the ages

We add up all the given ages: \(23 + 48 + 52 + 34 + 22 + 53 + 18 + 23 + 32 + 27\). Let's calculate that: \(23+48 = 71\), \(71 + 52 = 123\), \(123+34 = 157\), \(157+22 = 179\), \(179+53 = 232\), \(232+18 = 250\), \(250+23 = 273\), \(273+32 = 305\), \(305+27 = 332\).

Step2: Divide by the number of passengers

There are 10 passengers, so we divide the sum by 10: \(\frac{332}{10}=33.2\), and when we round to the nearest integer, we get 33. Wait, but let's check the addition again. Wait, the data is {23, 48, 52, 34, 22, 53, 18, 23, 32, 27}. Let's sum again: 23+23 = 46; 48+52 = 100; 34+22 = 56; 53+18 = 71; 32+27 = 59. Now sum these results: 46+100 = 146; 146+56 = 202; 202+71 = 273; 273+59 = 332. Yes, sum is 332. Then mean is \(332\div10 = 33.2\), rounded to nearest integer is 33. But looking at the options, maybe there was a typo in the data? Wait, maybe the data is {23, 48, 52, 34, 22, 53, 18, 23, 32, 27} – wait, 10 numbers. Wait, maybe I miscalculated. Wait 23+48=71, +52=123, +34=157, +22=179, +53=232, +18=250, +23=273, +32=305, +27=332. Yes. So mean is 33.2, nearest integer 33. But the options: maybe the original data was different? Wait, maybe the user made a typo, but assuming the data is correct, the mean rounded is 33. But if we check the options, maybe one of them is 33? Wait the options shown are "33 years", "34 years", "31 years", "333 years". So the correct one is 33 years.

Answer:

33 years