Question

adding & subtracting fractions coloring activity
solve each problem. circle your answer choices from the three choices given. find the problem number on the coloring sheet and color each section according to the color that corresponds with your answer choice.

	problem	answer choice #1	answer choice #2	answer choice #3	answer choice #4
2.	⅗ + ½	1 ¹/₁₀ green	³/₁₀ purple	2 ¹/₁₀ orange	⁶/₁₀ red
3.	⅓ + ¾	1 ¹/₁₂ purple	2 ²/₁₂ brown	1 ½ black	2 ½ orange
4.	1 ¾ - ½	1 ¼ red	1 yellow	1 ½ orange	1 ¾ purple
5.	3 ⅔ - 1 ¼	3 ³/₁₂ yellow	1 ⁵/₁₂ orange	2 ⅙ red	2 ⁵/₁₂ black
6.	3 ½ - 2 ⅗	¹/₁₀ black	1 ⁹/₁₀ purple	1 ¹/₁₀ yellow	⁹/₁₀ green
7.	1 ½ + 4 ⅝	6 ¼ red	6 yellow	6 ⅛ black	6 ⅜ orange
8.	6 ⅔ + 2 ½	9 brown	9 ⅙ orange	9 ⅙ purple	9 ½ yellow
9.	7 ⅛ - 3 ¼	4 ⅙ red	3 ⅛ yellow	3 ⅛ orange	4 ⅞ black
10.	9 ¼ + 3 ⅝	13 ½ red	13 ⅝ purple	12 yellow	12 ⅞ orange
11.	3 ⅓ - 1 ½	2 ⅙ orange	1 ⅚ purple	2 ⅚ red	1 ⅚ green
12.	5 ⅔ - 3 ⅘	2 ⅔ orange	2 ⅔ green	1 ⅗ red	1 ⅗ yellow

Explanation:

Step1: Find common - denominator for 1.

For $\frac{1}{2}+\frac{3}{4}$, the common denominator of 2 and 4 is 4. So $\frac{1}{2}=\frac{2}{4}$, and $\frac{2}{4}+\frac{3}{4}=\frac{2 + 3}{4}=\frac{5}{4}=1\frac{1}{4}$.

Step2: Find common - denominator for 2.

For $\frac{3}{5}+\frac{1}{2}$, the common denominator of 5 and 2 is 10. So $\frac{3}{5}=\frac{6}{10}$ and $\frac{1}{2}=\frac{5}{10}$, then $\frac{6}{10}+\frac{5}{10}=\frac{6 + 5}{10}=1\frac{1}{10}$.

Step3: Find common - denominator for 3.

For $\frac{1}{3}+\frac{3}{4}$, the common denominator of 3 and 4 is 12. So $\frac{1}{3}=\frac{4}{12}$ and $\frac{3}{4}=\frac{9}{12}$, then $\frac{4}{12}+\frac{9}{12}=\frac{4+9}{12}=1\frac{1}{12}$.

Step4: Find common - denominator for 4.

For $1\frac{3}{4}-\frac{1}{2}$, rewrite $1\frac{3}{4}=\frac{7}{4}$ and $\frac{1}{2}=\frac{2}{4}$, then $\frac{7}{4}-\frac{2}{4}=\frac{7 - 2}{4}=1\frac{1}{4}$.

Step5: Find common - denominator for 5.

For $3\frac{2}{3}-1\frac{1}{4}$, rewrite $3\frac{2}{3}=\frac{11}{3}$ and $1\frac{1}{4}=\frac{5}{4}$. The common denominator of 3 and 4 is 12. So $\frac{11}{3}=\frac{44}{12}$ and $\frac{5}{4}=\frac{15}{12}$, then $\frac{44}{12}-\frac{15}{12}=\frac{44 - 15}{12}=2\frac{5}{12}$.

Step6: Find common - denominator for 6.

For $3\frac{1}{2}-2\frac{3}{5}$, rewrite $3\frac{1}{2}=\frac{7}{2}$ and $2\frac{3}{5}=\frac{13}{5}$. The common denominator of 2 and 5 is 10. So $\frac{7}{2}=\frac{35}{10}$ and $\frac{13}{5}=\frac{26}{10}$, then $\frac{35}{10}-\frac{26}{10}=\frac{9}{10}$.

Step7: Find common - denominator for 7.

For $1\frac{1}{2}+4\frac{5}{8}$, rewrite $1\frac{1}{2}=\frac{3}{2}$ and $4\frac{5}{8}=\frac{37}{8}$. The common denominator of 2 and 8 is 8. So $\frac{3}{2}=\frac{12}{8}$, then $\frac{12}{8}+\frac{37}{8}=\frac{12 + 37}{8}=6\frac{1}{8}$.

Step8: Find common - denominator for 8.

For $6\frac{2}{3}+2\frac{1}{2}$, rewrite $6\frac{2}{3}=\frac{20}{3}$ and $2\frac{1}{2}=\frac{5}{2}$. The common denominator of 3 and 2 is 6. So $\frac{20}{3}=\frac{40}{6}$ and $\frac{5}{2}=\frac{15}{6}$, then $\frac{40}{6}+\frac{15}{6}=\frac{40 + 15}{6}=9\frac{1}{6}$.

Step9: Find common - denominator for 9.

For $7\frac{1}{6}-3\frac{1}{4}$, rewrite $7\frac{1}{6}=\frac{43}{6}$ and $3\frac{1}{4}=\frac{13}{4}$. The common denominator of 6 and 4 is 12. So $\frac{43}{6}=\frac{86}{12}$ and $\frac{13}{4}=\frac{39}{12}$, then $\frac{86}{12}-\frac{39}{12}=4\frac{1}{12}$.

Step10: Find common - denominator for 10.

For $9\frac{1}{4}+3\frac{5}{8}$, rewrite $9\frac{1}{4}=\frac{37}{4}$ and $3\frac{5}{8}=\frac{29}{8}$. The common denominator of 4 and 8 is 8. So $\frac{37}{4}=\frac{74}{8}$, then $\frac{74}{8}+\frac{29}{8}=\frac{74 + 29}{8}=12\frac{7}{8}$.

Step11: Find common - denominator for 11.

For $3\frac{1}{3}-1\frac{1}{2}$, rewrite $3\frac{1}{3}=\frac{10}{3}$ and $1\frac{1}{2}=\frac{3}{2}$. The common denominator of 3 and 2 is 6. So $\frac{10}{3}=\frac{20}{6}$ and $\frac{3}{2}=\frac{9}{6}$, then $\frac{20}{6}-\frac{9}{6}=1\frac{5}{6}$.

Step12: Find common - denominator for 12.

For $5\frac{2}{5}-3\frac{4}{5}$, rewrite $5\frac{2}{5}=\frac{27}{5}$ and $3\frac{4}{5}=\frac{19}{5}$, then $\frac{27}{5}-\frac{19}{5}=\frac{27 - 19}{5}=1\frac{3}{5}$.

Answer:

1. $1\frac{1}{4}$ yellow
2. $1\frac{1}{10}$ green
3. $1\frac{1}{12}$ purple
4. $1\frac{1}{4}$ red
5. $2\frac{5}{12}$ black
6. $\frac{9}{10}$ green
7. $6\frac{1}{8}$ orange
8. $9\frac{1}{6}$ purple
9. $4\frac{1}{12}$ red
10. $12\frac{7}{8}$ orange
11. $1\frac{5}{6}$ purple
12. $1\frac{3}{5}$ yellow