Question

add or subtract.
$2\sqrt{9} - 3 + \sqrt{3}$
$2\sqrt{9} - 3 + \sqrt{3} = \square$
(type an exact answer, using radicals as needed. simplify your answer.)

Explanation:

Step1: Simplify the square root

We know that $\sqrt{9} = 3$, so we substitute this value into the expression.
The expression $2\sqrt{9}-3+\sqrt{3}$ becomes $2\times3 - 3+\sqrt{3}$.

Step2: Perform the arithmetic operations

First, calculate $2\times3=6$. Then, we have $6 - 3+\sqrt{3}$.
Subtract 3 from 6: $6-3 = 3$. So the expression simplifies to $3+\sqrt{3}$.

Answer:

$3+\sqrt{3}$