Question

1. ( ab = ad + db )( cb = ce + eb )segment addition6. ( \frac{ad + db}{db}=\frac{ce + eb}{eb} )substitution property of equality7. ( \frac{ad}{db}+1=\frac{ce}{eb}+1 )division8. ( \frac{ad}{db}=\frac{ce}{eb} )subtraction property of equalitywhat is the missing statement in the proof? scroll down to see the entire proof.a. ( \frac{ab}{db}=\frac{ce}{eb} )b. ( \frac{ab}{cb}=\frac{db}{eb} )c. ( \frac{ab}{db}=\frac{cb}{eb} )d. ( \frac{ab}{cb}=\frac{ac}{de} )

Explanation:

Step1: Analyze the substitution

Since \(AB = AD + DB\) and \(CB=CE + EB\), when substituting into \(\frac{AD + DB}{DB}=\frac{CE + EB}{EB}\), we get \(\frac{AB}{DB}=\frac{CB}{EB}\).

Answer:

C. \(\frac{AB}{DB}=\frac{CB}{EB}\)