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Question
aaron is making building blocks. the blocks are shaped like triangular prisms with two triangular faces and three rectangular faces. what is the surface area of each block? a 136 cm² b 124 cm² c 106 cm² d 110 cm²
Step1: Calculate the area of the triangular faces
The formula for the area of a triangle is \(A = \frac{1}{2}bh\). Here, \(b = 4\space cm\) and \(h=3.5\space cm\).
For two triangular faces: \(2\times\frac{1}{2}\times4\times3.5= 14\space cm^{2}\)
Step2: Calculate the area of the rectangular faces
There are three rectangular faces.
- One with dimensions \(4\times8\): \(A_1=4\times8 = 32\space cm^{2}\)
- One with dimensions \(4\times8\): \(A_2 = 4\times8=32\space cm^{2}\)
- One with dimensions \(4\times8\): \(A_3=4\times8 = 32\space cm^{2}\)
The sum of the areas of the rectangular faces is \(32 + 32+32=96\space cm^{2}\)
Step3: Calculate the total surface area
The total surface area \(S\) of the triangular prism is the sum of the areas of the triangular and rectangular faces.
\(S=14 + 96=110\space cm^{2}\)
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D. \(110\space cm^{2}\)