Question

a2. reflect all of the coordinates from the previous slide over the y - axis and state the coordinates below.

Explanation:

Step1: Recall the reflection rule

When reflecting a point \((x,y)\) over the \(y -\)axis, the rule is \((x,y)\to(-x,y)\).

Step2: Apply the rule to each coordinate

• For the point \((- 6,5)\):

Using the rule \((x,y)\to(-x,y)\), when \(x=-6\) and \(y = 5\), the new \(x\) is \(-(-6)=6\) and \(y\) remains \(5\). So the new coordinate is \((6,5)\).

• For the point \((-3,8)\):

When \(x=-3\) and \(y = 8\), the new \(x\) is \(-(-3)=3\) and \(y\) remains \(8\). So the new coordinate is \((3,8)\).

• For the point \((0,8)\):

When \(x = 0\) and \(y=8\), since \(-0 = 0\), the new coordinate is \((0,8)\).

• For the point \((-6,-1)\):

When \(x=-6\) and \(y=-1\), the new \(x\) is \(-(-6)=6\) and \(y\) remains \(-1\). So the new coordinate is \((6,-1)\).

• For the point \((-3,-2)\):

When \(x=-3\) and \(y=-2\), the new \(x\) is \(-(-3)=3\) and \(y\) remains \(-2\). So the new coordinate is \((3,-2)\).

• For the point \((0,-2)\):

When \(x = 0\) and \(y=-2\), since \(-0=0\), the new coordinate is \((0,-2)\).

Answer:

New \(X\)	New \(Y\)
\(3\)	\(8\)
\(0\)	\(8\)
\(6\)	\(-1\)
\(3\)	\(-2\)
\(0\)	\(-2\)