Question

p(-7,2) is rotated 270° (counterclockwise) about the origin. name the quadrant p is located in. enter the option number that corresponds to your answer. option #1: quadrant i option #2: quadrant ii option #3: quadrant iii option #4: quadrant iv (1 point) p is located in option #

Explanation:

Step1: Recall rotation rule

The rule for rotating a point $(x,y)$ counter - clockwise by $270^{\circ}$ about the origin is $(x,y)\to(y, - x)$.

Step2: Apply the rule to point $P(-7,2)$

For point $P(-7,2)$, when we apply the rule, we get $P'(2,7)$.

Step3: Determine the quadrant

In the coordinate plane, a point $(x,y)$ with $x>0$ and $y > 0$ lies in Quadrant I. Since $P'(2,7)$ has $x = 2>0$ and $y=7>0$, it is in Quadrant I.

Answer:

Option #1: Quadrant I