Question

3(3x - 5) = 4(x + 3) + 8; 4x + 10 = 4x + 12 + 8; 6x + 10 = 4x + 20; 10 = 2x + 20; 30 =

Explanation:

Step1: Solve the equation \(3(3x - 5)=4(x + 3)+8\)

First, expand both sides of the equation.
Left side: \(3\times3x-3\times5 = 9x - 15\)
Right side: \(4\times x+4\times3 + 8=4x + 12 + 8=4x+20\)
So the equation becomes \(9x - 15=4x + 20\)

Step2: Move the terms with \(x\) to one side and constants to the other

Subtract \(4x\) from both sides: \(9x-4x - 15=4x-4x + 20\), which simplifies to \(5x - 15=20\)
Then add 15 to both sides: \(5x-15 + 15=20 + 15\), so \(5x=35\)

Step3: Solve for \(x\)

Divide both sides by 5: \(\frac{5x}{5}=\frac{35}{5}\), so \(x = 7\)

Answer:

\(x = 7\)