Question

3x² - 12 = 0
solutions ?

Explanation:

Step1: Isolate the \(x^2\) term

Add 12 to both sides of the equation \(3x^2 - 12 = 0\), we get \(3x^2 = 12\). Then divide both sides by 3: \(\frac{3x^2}{3}=\frac{12}{3}\), which simplifies to \(x^2 = 4\).

Step2: Solve for \(x\)

Take the square root of both sides. Remember that if \(x^2 = a\) (\(a\geq0\)), then \(x=\pm\sqrt{a}\). So for \(x^2 = 4\), we have \(x = \pm\sqrt{4}=\pm2\).

Answer:

\(x = 2\) or \(x = -2\)