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Question
- which polygon has an interior angle sum of 3960°? show work
Step1: Recall the formula for the sum of interior angles
The formula for the sum of interior angles of a polygon is \(S=(n - 2)\times180^{\circ}\), where \(n\) is the number of sides of the polygon.
Step2: Substitute \(S = 3960^{\circ}\) into the formula
We have \(3960=(n - 2)\times180\).
Step3: Solve for \(n\)
First, divide both sides of the equation by \(180\): \(\frac{3960}{180}=n - 2\).
Since \(\frac{3960}{180}=22\), then \(22=n - 2\).
Add \(2\) to both sides: \(n=22 + 2=24\).
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The polygon has \(24\) sides.