Question

30.
identify the x intercept.

x	0	1	3	4
y	-1	0	3	8

model (circle one):
linear growth quadratic (local max) exponential growth
linear decay quadratic (local min) exponential decay
options:
f(0) = 1
f(-1) = 0
f(0) = -1
f(1) = 0

Explanation:

Step1: Recall the definition of x - intercept

The x - intercept of a function \(y = f(x)\) is the value of \(x\) for which \(y=f(x)=0\).

Step2: Check the given function values

We are given four options:

• For \(f(0)=1\), when \(x = 0\), \(y=1

eq0\).

• For \(f(-1)=0\), we need to check if \(-1\) is in the domain of \(x\) values (the \(x\) values given are \(0,1,3,4\)). Since \(-1\) is not in the given \(x\) values of the table, this is not relevant.
• For \(f(0)=-1\), when \(x = 0\), \(y=-1

eq0\).

• For \(f(1)=0\), when \(x = 1\), \(y = 0\). And \(x = 1\) is in the set of \(x\) values \(\{0,1,3,4\}\) from the table.

Answer:

\(f(1)=0\)