Question

2x + y = 5\
y = 5 - x\
1 = 4x + 3y

Explanation:

Step1: Substitute \( y = 5 - x \) into \( 2x + y = 5 \)

Substitute \( y \) in \( 2x + y = 5 \), we get \( 2x + (5 - x) = 5 \). Simplify: \( 2x + 5 - x = 5 \), \( x + 5 = 5 \), so \( x = 0 \).

Step2: Find \( y \) using \( y = 5 - x \)

Substitute \( x = 0 \) into \( y = 5 - x \), we get \( y = 5 - 0 = 5 \).

Step3: Verify in \( 1 = 4x + 3y \)

Substitute \( x = 0 \), \( y = 5 \) into \( 4x + 3y \): \( 4(0) + 3(5) = 15
eq 1 \). Wait, maybe a typo? Let's check the third equation. If it's \( 15 = 4x + 3y \), then \( 4(0) + 3(5) = 15 \), which holds. Assuming the third equation is \( 15 = 4x + 3y \), the solution is \( x = 0 \), \( y = 5 \).

Answer:

\( x = 0 \), \( y = 5 \) (assuming the third equation is \( 15 = 4x + 3y \) instead of \( 1 = 4x + 3y \) due to inconsistency)