Question

\\((x+4)(2x+3)(4-x)\\)

Explanation:

Rearrange the factors

$$ (x+4)(4-x)(2x+3) = (16-x^2)(2x+3) $$

Expand the remaining product

$$ (16-x^2)(2x+3) = 16(2x+3) - x^2(2x+3) $$

Simplify to standard form

$$ 32x + 48 - 2x^3 - 3x^2 = -2x^3 - 3x^2 + 32x + 48 $$

Answer:

\(-2x^3 - 3x^2 + 32x + 48\)