QUESTION IMAGE
Question
- select all that apply: in an isosceles triangle, if ab = ac, where does the perpendicular bisector of bc intersect the triangle? midpoint of bc at vertex c at vertex b at vertex a
Brief Explanations
- Midpoint of BC: By definition, a perpendicular bisector of a segment (here, \( BC \)) passes through its midpoint. So the perpendicular bisector of \( BC \) must intersect \( BC \) at its midpoint.
- At vertex A: In an isosceles triangle with \( AB = AC \), the triangle is symmetric about the line that is the perpendicular bisector of \( BC \). This line also passes through vertex \( A \) (since \( AB = AC \), \( A \) lies on the perpendicular bisector of \( BC \)).
- At vertex B/C: The perpendicular bisector of \( BC \) is perpendicular to \( BC \) and passes through its midpoint. Vertex \( B \) and \( C \) lie on \( BC \), but the perpendicular bisector is not at \( B \) or \( C \) (unless \( BC = 0 \), which is impossible for a triangle). So these are incorrect.
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- Midpoint of BC
- At vertex A