Question

1. $5 + 2(-6y - 2) - 5y$
2. $9 - 4(2p + 3) - 8p + 7$
3. $-11x - (x - 3) - 12 + 4x$
4. $-x + 2(3x + y) - 5y + 10x$

Explanation:

Step1: Expand the bracket

First, we expand the bracket in the expression \(5 + 2(-6y - 2)-5y\). Using the distributive property \(a(b + c)=ab+ac\), we get:
\(5+2\times(-6y)+2\times(-2)-5y = 5-12y - 4-5y\)

Step2: Combine like terms

Next, we combine the constant terms and the terms with \(y\) separately. The constant terms are \(5\) and \(-4\), and the terms with \(y\) are \(-12y\) and \(-5y\).
Combining the constant terms: \(5 - 4=1\)
Combining the terms with \(y\): \(-12y-5y=-17y\)

Step3: Write the final expression

Putting the combined terms together, we get \(1-17y\) or \(-17y + 1\)

Answer:

\(\boldsymbol{-17y + 1}\) (or \(\boldsymbol{1-17y}\))