Question

1. $35,800 at 1% for \\(\frac{3}{4}\\) years
2. $1,020 at 6% for \\(2\frac{1}{2}\\) years
3. $405 at 16% for \\(8\frac{3}{4}\\) years
4. $7,800 at 12% for 2 years
5. $17,300 at 14% for \\(\frac{3}{4}\\) years
6. $34,000 at 8% for \\(4\frac{1}{2}\\) years
7. $1,150 at 10% for 7 years
8. $52,200 at 4% for \\(6\frac{3}{4}\\) years
9. $1,760 at 7% for 2 years
10. $7,600 at 15% for 2 years
11. $35 at 2.9% for \\(\frac{1}{4}\\) years
12. $17,300 at 1% for \\(1\frac{1}{2}\\) years
13. $37,000 at 1.2% for \\(2\frac{3}{4}\\) years
14. $48,200 at 2.9% for 2 years
15. $1,200 at 1% for \\(4\frac{1}{4}\\) years
16. $1,940 at 5.6% for 9 years
17. $13,700 at 5% for 3 years
18. $44,600 at 1.3% for 5 years
19. $650 at 3.6% for \\(5\frac{1}{4}\\) years

Explanation:

Let's solve problem 22: $\$35,800$ at $1\%$ for $\frac{3}{4}$ years. We use the simple interest formula $I = P \times r \times t$, where $P$ is the principal amount, $r$ is the annual interest rate (in decimal), and $t$ is the time in years.

Step 1: Identify the values

• Principal ($P$) = $\$35,800$
• Rate ($r$) = $1\% = 0.01$ (converted to decimal)
• Time ($t$) = $\frac{3}{4}$ years

Step 2: Substitute into the formula

$I = 35800 \times 0.01 \times \frac{3}{4}$

First, calculate $35800 \times 0.01 = 358$

Then, calculate $358 \times \frac{3}{4} = \frac{358 \times 3}{4} = \frac{1074}{4} = 268.5$

Answer:

The simple interest for problem 22 is $\$268.50$