Question

1. for a population with a mean of $mu = 72$ and a stan-dard deviation of $sigma = 10$, what is the standard error

Explanation:

Step1: Recall the formula for standard error

The formula for the standard error of the mean is $\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}$.

Step2: Assume sample size (since it's not given, maybe a typo and assume \(n = 1\) as a default for population - related standard error concept check, but if it's about sampling distribution and \(n\) is missing, perhaps it's a mistake. However, if we consider the formula structure):

If we assume \(n = 1\) (for the sake of showing the formula application, though in a proper sampling context \(n\) should be given). Then $\sigma_{\bar{x}}=\frac{10}{\sqrt{1}}$.

Answer:

If \(n = 1\), the standard error is \(10\). But if this is a sampling - distribution problem and \(n\) was omitted in the problem statement, the formula is $\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}$ where \(\sigma = 10\) and \(n\) is the sample size.