Question

2-6 analyze y = mx + b: additional practice
2.8ap-1
what is the graph of the equation ( y = -\frac{1}{4}x + 2 )?
the y-intercept is 2, which means the line crosses the y-axis at the point (type integers or fractions. simplify your answers.)

Explanation:

Step1: Recall the slope - intercept form

The equation of a line in slope - intercept form is \(y = mx + b\), where \(b\) is the \(y\) - intercept.
In the given equation \(y=-\frac{1}{4}x + 2\), \(b = 2\).

Step2: Find the \(y\) - axis crossing point

When \(x = 0\), \(y=-\frac{1}{4}(0)+2\).
Since \(x = 0\) on the \(y\) - axis, substituting \(x = 0\) into the equation \(y=-\frac{1}{4}x + 2\) gives \(y=2\). So the line crosses the \(y\) - axis at the point \((0,2)\).

Answer:

The line crosses the \(y\) - axis at the point \((0,2)\)