Question

1. 198 = -6(5c + 2 )

Explanation:

Step1: Divide both sides by -6

To isolate the term with \( c \), we divide both sides of the equation \( 198 = -6(5c + 2) \) by \(-6\).
\[
\frac{198}{-6}=\frac{-6(5c + 2)}{-6}
\]
Simplifying both sides, we get \(-33 = 5c + 2\).

Step2: Subtract 2 from both sides

Now, we want to isolate the term with \( c \), so we subtract 2 from both sides of the equation \(-33 = 5c + 2\).
\[
-33 - 2=5c + 2 - 2
\]
Simplifying both sides, we have \(-35 = 5c\).

Step3: Divide both sides by 5

To solve for \( c \), we divide both sides of the equation \(-35 = 5c\) by 5.
\[
\frac{-35}{5}=\frac{5c}{5}
\]
Simplifying both sides, we find that \( c=-7 \).

Answer:

\( c = -7 \)