Question

1. $30 = 10a$
2. $21 = 3n$
3. $-45 = 9k$
4. $-90 = 10x$
5. $4 = -4p$
6. $56 = -7n$
7. $-32 = -8x$
8. $-80 = -10n$
9. $10 = \frac{x}{8}$
10. $3 = \frac{m}{6}$
11. $-8 = \frac{n}{10}$
12. $-9 = \frac{x}{3}$
13. $9 = \frac{r}{-2}$
14. $7 = \frac{k}{-3}$
15. $-9 = \frac{m}{-8}$
16. $-1 = \frac{k}{-10}$
17. $0 = -7b$
18. $3 = \frac{m}{4}$

Explanation:

Let's solve each equation one by one:

Problem 19: \( 30 = 10a \)

Step 1: Divide both sides by 10

To isolate \( a \), we divide both sides of the equation by 10.
\( \frac{30}{10} = \frac{10a}{10} \)

Step 2: Simplify

Simplifying both sides gives us the value of \( a \).
\( 3 = a \) or \( a = 3 \)

Step 1: Divide both sides by 3

To isolate \( n \), we divide both sides of the equation by 3.
\( \frac{21}{3} = \frac{3n}{3} \)

Step 2: Simplify

Simplifying both sides gives us the value of \( n \).
\( 7 = n \) or \( n = 7 \)

Step 1: Divide both sides by 9

To isolate \( k \), we divide both sides of the equation by 9.
\( \frac{-45}{9} = \frac{9k}{9} \)

Step 2: Simplify

Simplifying both sides gives us the value of \( k \).
\( -5 = k \) or \( k = -5 \)

Answer:

\( a = 3 \)

Problem 20: \( 21 = 3n \)