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18. solve for the missing arc lh. a. 125° b. 130° c. 144° d. 165°

Question

  1. solve for the missing arc lh.

a. 125°
b. 130°
c. 144°
d. 165°

Explanation:

Step1: Recall the formula for the measure of an angle formed by two secants

The measure of an angle formed by two secants outside a circle is \(\frac{1}{2}(m\overset{\frown}{LH}-m\overset{\frown}{EG})\). Let \(m\angle EFG = 37^{\circ}\) and \(m\overset{\frown}{EG}=51^{\circ}\), and \(m\overset{\frown}{LH}=x\). The formula is \(\angle EFG=\frac{1}{2}(m\overset{\frown}{LH} - m\overset{\frown}{EG})\).

Step2: Substitute the known values into the formula

We have \(37^{\circ}=\frac{1}{2}(x - 51^{\circ})\).

Step3: Solve the equation for \(x\)

Multiply both sides of the equation by \(2\): \(37^{\circ}\times2=x - 51^{\circ}\). So, \(74^{\circ}=x - 51^{\circ}\).
Add \(51^{\circ}\) to both sides: \(x=74^{\circ}+ 51^{\circ}+6^{\circ}\) (Wait, no, correct calculation: \(37\times2 = 74\), then \(x=74 + 56\) (Wait, no, correct formula application:

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So the measure of arc \(LH\) is \(130^{\circ}\).

Answer:

B. \(130^{\circ}\)