Question

1. right triangle with one leg labeled 6.5, base labeled 9.9, right angle at the top vertex

Explanation:

Assuming we need to find the other leg of the right triangle (let's call it \( x \)) using the Pythagorean theorem \( a^2 + b^2 = c^2 \), where \( c = 9.9 \) (hypotenuse) and \( a = 6.5 \) (one leg).

Step 1: Rearrange the formula

We solve for \( b \): \( b = \sqrt{c^2 - a^2} \)

Step 2: Substitute the values

Substitute \( c = 9.9 \) and \( a = 6.5 \):
\( b = \sqrt{9.9^2 - 6.5^2} \)
First, calculate \( 9.9^2 = 98.01 \) and \( 6.5^2 = 42.25 \)
Then, \( 98.01 - 42.25 = 55.76 \)
So, \( b = \sqrt{55.76} \approx 7.47 \)

Answer:

The length of the other leg is approximately \( 7.47 \) (if finding the other leg; adjust based on actual question, e.g., area would be \( \frac{1}{2} \times 6.5 \times 7.47 \approx 24.3 \))