Question

1. the perimeter of the rectangle was 34 feet. if the length of the rectangle was 9 feet, how wide was the rectangle?

Explanation:

Step1: Recall the perimeter formula

The perimeter formula of a rectangle is \(P = 2(l + w)\), where \(P\) is the perimeter, \(l\) is the length, and \(w\) is the width.

Step2: Substitute the known values

Given \(P = 34\) feet and \(l=9\) feet. Substitute into the formula: \(34 = 2(9 + w)\).

Step3: Simplify the equation

First, divide both sides of the equation by \(2\): \(\frac{34}{2}=\frac{2(9 + w)}{2}\), which gives \(17=9 + w\).

Step4: Solve for \(w\)

Subtract \(9\) from both sides: \(w=17 - 9\).

Answer:

\(8\) feet