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Question
- triangle xyz with sides: xz = 25m, xy = 27m, yz = 24m
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Using Heron's formula:
First, find the semi - perimeter \(s=\frac{24 + 25+27}{2}=\frac{76}{2} = 38\) m.
Then, the area \(A=\sqrt{s(s - a)(s - b)(s - c)}=\sqrt{38(38 - 24)(38 - 25)(38 - 27)}=\sqrt{38\times14\times13\times11}=\sqrt{76076}\approx276\) \(m^{2}\).