Question

1. -/1 points details my notes practice another suppose that you must order concrete for a sidewalk that is to be 50 ft by 6 ft to a depth of 3 in. how much concrete is required? (answer to the nearest \\( \frac{1}{2} \\) cubic yard.) \\( \mathrm{yd}^{3} \\)

Explanation:

Step1: Convert units

First, convert all units to yards. Since \(1\) yard \( = 3\) feet and \(1\) yard \(=36\) inches.
The length \(l = 50\) ft \(=\frac{50}{3}\) yd, the width \(w = 6\) ft \(=\frac{6}{3}=2\) yd, and the depth \(h = 3\) in \(=\frac{3}{36}=\frac{1}{12}\) yd.

Step2: Calculate the volume

The volume \(V\) of a rectangular - prism (which the sidewalk is modeled as) is given by \(V=l\times w\times h\).
Substitute the values: \(V=\frac{50}{3}\times2\times\frac{1}{12}\).

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Rounding to the nearest \(\frac{1}{2}\) cubic - yard, \(\frac{25}{9}\approx2.8\), and \(2.8\approx3.0\) (since \(2.8\) is closer to \(3.0\) than to \(2.5\)).

Answer:

\(3\)