QUESTION IMAGE
Question
- in the california state lottery, you must select six numbers from fifty - two numbers to win the big prize. the numbers do not have to be in a particular order. what is the probability that you will win the big prize if you buy one ticket?
$_{n}c_{r}=\frac{n!}{n!r!}$
$=\frac{52!}{5!6!}$
Step1: Identify the combination formula
The problem involves selecting 6 numbers from 52, where order doesn't matter. The combination formula is \( _nC_r=\frac{n!}{r!(n - r)!} \), where \( n = 52 \) and \( r = 6 \).
Step2: Calculate the number of possible combinations
Substitute \( n = 52 \) and \( r = 6 \) into the formula:
Simplify \( 52! = 52×51×50×49×48×47×46! \), so:
Calculate the numerator: \( 52×51 = 2652 \), \( 2652×50 = 132600 \), \( 132600×49 = 6497400 \), \( 6497400×48 = 311875200 \), \( 311875200×47 = 14658134400 \)
Calculate the denominator: \( 6×5 = 30 \), \( 30×4 = 120 \), \( 120×3 = 360 \), \( 360×2 = 720 \), \( 720×1 = 720 \)
Now divide: \( \frac{14658134400}{720}=20358520 \)
Step3: Determine the probability
There is 1 winning combination. So the probability \( P=\frac{1}{_{52}C_6}=\frac{1}{20358520} \)
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The probability is \(\frac{1}{20358520}\)