Question

1. which table contains only corresponding x-values and y-values where the value of y is 3 more than the quotient of x and 2? a. x y 7 5 10 6.5 14 8.5 17 10 b. x y 7 3.5 10 5 14 7 17 8.5 c. x y 7 6.5 10 8 14 10 17 11.5 d. x y 7 0.5 10 2 14 4 17 5.5 16. a teacher bought mar the teacher had a $2 total cost of the mark which table shows th number of sets of ma and y, the total cost o a sets of markers bought, x 3 9 12 24 b sets of markers bought, x 9 12 15 24 c sets of markers bought, x

Explanation:

Step1: Define the equation

The problem states that \( y \) is 3 more than the quotient of \( x \) and 2. So the equation is \( y=\frac{x}{2}+3 \).

Step2: Test option A

For \( x = 7 \): \( y=\frac{7}{2}+3=3.5 + 3 = 6.5 \), but table A has \( y = 5 \) for \( x = 7 \). So A is incorrect.

Step3: Test option B

For \( x = 7 \): \( y=\frac{7}{2}+3=3.5+3 = 6.5 \), but table B has \( y = 3.5 \) for \( x = 7 \). So B is incorrect.

Step4: Test option C

For \( x = 7 \): \( y=\frac{7}{2}+3=3.5 + 3=6.5 \), which matches the table. For \( x = 10 \): \( y=\frac{10}{2}+3 = 5+3=8 \), which matches. For \( x = 14 \): \( y=\frac{14}{2}+3=7 + 3 = 10 \), which matches. For \( x = 17 \): \( y=\frac{17}{2}+3=8.5+3 = 11.5 \), which matches.

Step5: Test option D (optional, but to confirm)

For \( x = 7 \): \( y=\frac{7}{2}+3=3.5 + 3=6.5 \), but table D has \( y = 0.5 \) for \( x = 7 \). So D is incorrect.

Answer:

C.

\( x \)	\( y \)
10	8
14	10
17	11.5