QUESTION IMAGE
Question
- x 14 51° 18.0
Step1: Use Pythagorean theorem
$$a^{2}+b^{2}=c^{2}$$
Here, \(a = 14\), \(b=18\), and \(c=x\)
Step2: Substitute values
$$x^{2}=14^{2}+18^{2}$$
$$x^{2}=196 + 324$$
$$x^{2}=520$$
Step3: Solve for \(x\)
$$x=\sqrt{520}\approx22.8$$
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\(x\approx22.8\)