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Question
for #13 - 17, find the value of x. 2 pts each.
13.
14.
15.
16.
17.
Step1: Use the triangle angle sum property (for 13)
The sum of angles in a triangle is \(180^{\circ}\). So, \(x + 34+51 = 180\).
Step2: Use the triangle angle sum property (for 14)
Let the two equal - base angles be \(y\). Since the sum of angles in a triangle is \(180^{\circ}\), \(x + 2y=180\). Also, if the base angles are \(62^{\circ}\) (assuming isosceles triangle from the figure), \(x=180-2\times62 = 180 - 124=56\)
Step3: Use the right - triangle angle sum property (for 15)
In a right - triangle (\(90^{\circ}\) angle), the sum of angles is \(180^{\circ}\). So, \(x+40 + 90=180\).
Step4: Use the exterior - angle property (for 16)
The exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles. So, \(x=52+55=107\)
Step5: Use the exterior - angle property (for 17)
The exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles. Let the exterior angle be \(180 - 68=112^{\circ}\). Then \(x+42=112\).
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- \(95\)
- \(56\)
- \(50\)
- \(107\)
- \(70\)