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(c) 120° 130° 110° 100° 135° x

Question

(c)
120°
130°
110°
100°
135°
x

Explanation:

Step1: Recall Hexagon Angle Sum

The sum of interior angles of a hexagon (6 - sided polygon) is given by the formula \((n - 2)\times180^{\circ}\), where \(n = 6\). So, \((6 - 2)\times180^{\circ}=4\times180^{\circ} = 720^{\circ}\).

Step2: Sum Known Angles

Add the known angles: \(120^{\circ}+130^{\circ}+100^{\circ}+135^{\circ}+110^{\circ}\).
Calculating: \(120 + 130 = 250\); \(250+100 = 350\); \(350+135 = 485\); \(485+110 = 595^{\circ}\).

Step3: Solve for \(x\)

Let the sum of all angles be \(720^{\circ}\). So, \(595^{\circ}+x = 720^{\circ}\).
Subtract \(595^{\circ}\) from both sides: \(x = 720^{\circ}- 595^{\circ}=125^{\circ}\).

Answer:

\(125^{\circ}\)