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Question
- write an equation in slope-intercept form for
- identify which lines are parallel: $y = -\frac{1}{2}x + 3$; $y = \frac{1}{2}x + 1$; $y = 2x$; $x + 2y = 4$.
- identify which lines are perpendicular: $y - 2 = 3x$; $y + 4x = -1$; $y = -\frac{1}{3}x + 5$; $y = \frac{1}{3}x - 4$.
- write an equation in slope-intercept form for the line that passes through $(0, 6)$ and is parallel to the line described by $y = 2x + 3$.
- write an equation in slope-intercept form for the line that passes through $(4, 6)$ and is perpendicular to the line described by $y = x - 3$.
Question 15
Step1: Recall slope-intercept form
Slope - intercept form is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y - intercept.
Step2: Determine the slope of the parallel line
If two lines are parallel, they have the same slope. The line \(y = 2x+3\) has a slope \(m = 2\). So the line we want to find also has a slope \(m = 2\).
Step3: Determine the y - intercept
The line passes through the point \((0,6)\). In the slope - intercept form \(y=mx + b\), when \(x = 0\), \(y=b\). So if the line passes through \((0,6)\), then \(b = 6\).
Step4: Write the equation
Substitute \(m = 2\) and \(b = 6\) into the slope - intercept form \(y=mx + b\). We get \(y=2x + 6\).
Step1: Recall slope - intercept form and perpendicular slope relationship
Slope - intercept form is \(y=mx + b\). If two lines are perpendicular, the product of their slopes is \(- 1\) (i.e., \(m_1\times m_2=-1\)).
Step2: Find the slope of the given line
The line \(y=x - 3\) has a slope \(m_1 = 1\). Let the slope of the perpendicular line be \(m_2\). Then \(1\times m_2=-1\), so \(m_2=-1\).
Step3: Use the point - slope form to find the equation
The point - slope form of a line is \(y - y_1=m(x - x_1)\), where \((x_1,y_1)=(4,6)\) and \(m=-1\). Substitute these values into the point - slope form:
\(y - 6=-1(x - 4)\)
Step4: Simplify to slope - intercept form
Expand the right - hand side: \(y-6=-x + 4\). Add 6 to both sides: \(y=-x+4 + 6\), so \(y=-x + 10\).
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\(y = 2x+6\)