QUESTION IMAGE
Question
- given: m is the midpoint of \\( \overline { j k } \\)
\\( j m = 5 \\)
prove: \\( m k = 5 \\)
- given: b is the midpoint of \\( \overline { a c } \\)
\\( a b = 3 x + 6 \\)
\\( b c = - 2 x + 26 \\)
prove: \\( x = 4 \\)
Step1: Use the mid - point property
Since \(B\) is the mid - point of \(\overline{AC}\), by the definition of a mid - point, \(AB = BC\).
So, \(3x + 6=-2x + 26\)
Step2: Solve the equation for \(x\)
Add \(2x\) to both sides of the equation:
\(3x+2x + 6=-2x+2x + 26\)
\(5x+6 = 26\)
Subtract \(6\) from both sides:
\(5x+6 - 6=26 - 6\)
\(5x=20\)
Divide both sides by \(5\):
\(x=\frac{20}{5}=4\)
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\(x = 4\)