QUESTION IMAGE
Question
12 the diagram shows shape x. make a copy of
the diagram.
a draw the image of x after a reflection in the line
x = -2, followed by a rotation of 90° clockwise
about the point (-1, 0), followed by a translation
(4
3), followed by a reflection in the line y = 1,
followed by a rotation of 90° anticlockwise about
the point (5, -1). label the image y.
b describe the single transformation that takes y to x.
Step1: Reflection in \(x = - 2\)
For a point \((x,y)\) reflected in the line \(x = a\), the formula is \((2a - x,y)\). Here \(a=-2\), for a general point \((x,y)\) its image is \((-4 - x,y)\).
Step2: Rotation of \(90^{\circ}\) clockwise
The rotation matrix for a \(90^{\circ}\) clockwise rotation about the origin is \(
\). If we have a point \((x,y)\), after rotation it becomes \((y,-x)\).
Step3: Translation
A translation \(
\) moves a point \((x,y)\) to \((x + h,y + k)\). Here \(
\), so \((x,y)\to(x + 3,y + 4)\).
Step4: Reflection in \(y = 1\)
For a point \((x,y)\) reflected in the line \(y=b\), the formula is \((x,2b - y)\). Here \(b = 1\), so \((x,y)\to(x,2 - y)\).
Step5: Rotation of \(90^{\circ}\) anticlockwise
The rotation matrix for a \(90^{\circ}\) anticlockwise rotation about the origin is \(
\). If we have a point \((x,y)\), after rotation it becomes \((-y,x)\).
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To draw the image in part (a), follow the sequence of transformations: reflection in \(x=-2\), then \(90^{\circ}\) clockwise rotation, then translation \(
\), then reflection in \(y = 1\). For part (b), since the composition of transformations is a sequence of isometries (reflections, rotations, translations), we can work backwards. The single transformation that takes \(Y\) to \(X\) is a rotation of \(90^{\circ}\) clockwise (the inverse of the \(90^{\circ}\) anticlockwise rotation in the reverse - order of transformations).