Question

1. a bicyclist rides 46 miles in 3 hours. how fast does she ride?
2. a swimmer swims the 500 - meter race in 300 seconds. what is the average speed of the swimmer?
3. what distance will a car traveling 65 km/hr travel in 3.2 hours?
4. the distance between milwaukee and chicago is 150 km and can be driven in 95 minutes.

a. what is the average speed in km/hr?
b. what is the average speed in m/s?

1. you are in a car going 120 km/hr.

a. how far will you have traveled in 10 minutes?
b. how far will you have traveled in 25 minutes?
c. how far will you have traveled in 40 minutes?
d. how far will you have traveled in 90 minutes?

1. a car is traveling at 110 km/hr.

a. how long will it take to go 55 km?
b. how long will it take to go 165 km?
c. how long will it take to go 330 km?
d. how long will it take to go 495 km?

Explanation:

12. Velocidad de la bicicleta

Utilizamos la fórmula $v=\frac{d}{t}$, donde $d$ es la distancia y $t$ es el tiempo.
$v=\frac{46\ \text{miles}}{3\ \text{horas}}\approx 15.33\ \text{miles/hora}$

13. Velocidad del nadador

Usando $v = \frac{d}{t}$, con $d = 500\ \text{m}$ y $t=300\ \text{s}$.
$v=\frac{500\ \text{m}}{300\ \text{s}}=\frac{5}{3}\ \text{m/s}\approx1.67\ \text{m/s}$

14. Distancia recorrida por el auto

Usamos la fórmula $d = v\times t$, con $v = 65\ \text{km/h}$ y $t = 3.2\ \text{horas}$.
$d=65\ \text{km/h}\times3.2\ \text{horas}=208\ \text{km}$

15. a. Velocidad promedio en km/h

Primero, convertimos los minutos a horas. $95\ \text{minutos}=\frac{95}{60}\ \text{horas}\approx1.583\ \text{horas}$.
Usando $v=\frac{d}{t}$, con $d = 150\ \text{km}$ y $t=\frac{95}{60}\ \text{horas}$.
$v=\frac{150\ \text{km}}{\frac{95}{60}\ \text{horas}}=\frac{150\times60}{95}\ \text{km/h}=\frac{1800}{19}\ \text{km/h}\approx94.74\ \text{km/h}$

15. b. Velocidad promedio en m/s

$150\ \text{km}=150000\ \text{m}$ y $95\ \text{minutos}=95\times60\ \text{s}=5700\ \text{s}$.
$v=\frac{150000\ \text{m}}{5700\ \text{s}}=\frac{500}{19}\ \text{m/s}\approx26.32\ \text{m/s}$

16. a. Distancia recorrida en 10 minutos

Convertimos 10 minutos a horas: $10\ \text{minutos}=\frac{10}{60}\ \text{horas}=\frac{1}{6}\ \text{horas}$.
Usando $d = v\times t$, con $v = 120\ \text{km/h}$ y $t=\frac{1}{6}\ \text{horas}$.
$d=120\ \text{km/h}\times\frac{1}{6}\ \text{horas}=20\ \text{km}$

16. b. Distancia recorrida en 25 minutos

Convertimos 25 minutos a horas: $25\ \text{minutos}=\frac{25}{60}\ \text{horas}=\frac{5}{12}\ \text{horas}$.
$d=120\ \text{km/h}\times\frac{5}{12}\ \text{horas}=50\ \text{km}$

16. c. Distancia recorrida en 40 minutos

Convertimos 40 minutos a horas: $40\ \text{minutos}=\frac{40}{60}\ \text{horas}=\frac{2}{3}\ \text{horas}$.
$d=120\ \text{km/h}\times\frac{2}{3}\ \text{horas}=80\ \text{km}$

16. d. Distancia recorrida en 90 minutos

Convertimos 90 minutos a horas: $90\ \text{minutos}=\frac{90}{60}\ \text{horas}=1.5\ \text{horas}$.
$d=120\ \text{km/h}\times1.5\ \text{horas}=180\ \text{km}$

17. a. Tiempo para recorrer 55 km

Usando $t=\frac{d}{v}$, con $d = 55\ \text{km}$ y $v = 110\ \text{km/h}$.
$t=\frac{55\ \text{km}}{110\ \text{km/h}} = 0.5\ \text{horas}$

17. b. Tiempo para recorrer 165 km

$t=\frac{165\ \text{km}}{110\ \text{km/h}}=1.5\ \text{horas}$

17. c. Tiempo para recorrer 330 km

$t=\frac{330\ \text{km}}{110\ \text{km/h}} = 3\ \text{horas}$

17. d. Tiempo para recorrer 495 km

$t=\frac{495\ \text{km}}{110\ \text{km/h}}=4.5\ \text{horas}$

Answer:

1. $15.33\ \text{miles/hora}$
2. $\frac{5}{3}\ \text{m/s}\approx1.67\ \text{m/s}$
3. $208\ \text{km}$
4. a. $\frac{1800}{19}\ \text{km/h}\approx94.74\ \text{km/h}$
5. b. $\frac{500}{19}\ \text{m/s}\approx26.32\ \text{m/s}$
6. a. $20\ \text{km}$
7. b. $50\ \text{km}$
8. c. $80\ \text{km}$
9. d. $180\ \text{km}$
10. a. $0.5\ \text{horas}$
11. b. $1.5\ \text{horas}$
12. c. $3\ \text{horas}$
13. d. $4.5\ \text{horas}$