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12. (7y - 20)° (3x - 4)° (5x - 38)° m l

Question

  1. (7y - 20)° (3x - 4)° (5x - 38)° m l

Explanation:

Step1: Find the value of \(x\)

Since \(m\parallel l\), then \((3x - 4)^{\circ}+(5x - 38)^{\circ}=90^{\circ}\) (complementary angles formed by a transversal intersecting parallel lines).

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Step2: Find the value of \(y\)

Also, \((7y - 20)^{\circ}+(5x - 38)^{\circ}=180^{\circ}\) (supplementary angles). Substitute \(x = 16.5\) into \((5x - 38)\):

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Then \(7y-20+44.5 = 180\)

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Answer:

\(x = 16.5\), \(y\approx22.2\)