Question

12/18 final exam
determine the median of the following measurements:
654, 23, 67, 32, 1, 34 the median is

Explanation:

Step1: Order the data

First, we need to arrange the given numbers in ascending order. The numbers are 654, 23, 67, 32, 1, 34. When we sort them from smallest to largest, we get: 1, 23, 32, 34, 67, 654.

Step2: Find the median position

For a set with \( n \) numbers, if \( n \) is even, the median is the average of the \( \frac{n}{2} \)-th and \( (\frac{n}{2}+1) \)-th values. Here, \( n = 6 \) (since there are 6 numbers), so \( \frac{n}{2}=3 \) and \( \frac{n}{2}+1 = 4 \).

Step3: Calculate the median

We take the 3rd and 4th values from the sorted list. The 3rd value is 32 and the 4th value is 34. The median is the average of these two values, so we calculate \( \frac{32 + 34}{2} \).
First, add 32 and 34: \( 32+34 = 66 \). Then divide by 2: \( \frac{66}{2}=33 \).

Answer:

33