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Question
- solve the inequality: $-2 \geq -9 + \frac{x}{2}$
a. $x \geq 2$
b. $x \geq -25$
c. $x \leq 14$
d. $x \leq 2$
Step1: Add 9 to both sides
To isolate the term with \( x \), we add 9 to both sides of the inequality \( -2 \geq -9 + \frac{x}{2} \). This gives us \( -2 + 9 \geq \frac{x}{2} \), which simplifies to \( 7 \geq \frac{x}{2} \).
Step2: Multiply both sides by 2
To solve for \( x \), we multiply both sides of the inequality \( 7 \geq \frac{x}{2} \) by 2. This gives us \( 7 \times 2 \geq x \), which simplifies to \( 14 \geq x \) or \( x \leq 14 \).
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C. \( x \leq 14 \)