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Question
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$overleftrightarrow{cd}$ is perpendicular to $overleftrightarrow{ab}$ and passes through point c(5, 12).
if the coordinates of a and b are (-10, -3) and (7, 14), respectively, the x - intercept of $overleftrightarrow{cd}$ is. the point lies on $overleftrightarrow{cd}$.
Step1: Find the slope of $\overleftrightarrow{AB}$
The slope formula is $m = \frac{y_2 - y_1}{x_2 - x_1}$. For points $A(-10,-3)$ and $B(7,14)$, $m_{AB}=\frac{14 - (-3)}{7-(-10)}=\frac{14 + 3}{7 + 10}=\frac{17}{17}=1$.
Step2: Find the slope of $\overleftrightarrow{CD}$
If two lines are perpendicular, the product of their slopes is - 1. Let the slope of $\overleftrightarrow{CD}$ be $m_{CD}$. Since $m_{AB}\times m_{CD}=-1$ and $m_{AB} = 1$, then $m_{CD}=-1$.
Step3: Find the equation of $\overleftrightarrow{CD}$
The point - slope form of a line is $y - y_1=m(x - x_1)$. Using the point $C(5,12)$ and $m=-1$, we have $y - 12=-1(x - 5)$, which simplifies to $y-12=-x + 5$ or $y=-x+17$.
Step4: Find the x - intercept of $\overleftrightarrow{CD}$
To find the x - intercept, set $y = 0$. Then $0=-x + 17$, so $x = 17$.
Step5: Check which point lies on $\overleftrightarrow{CD}$
Let's assume we have points to check. Substitute the x and y values of the point into the equation $y=-x + 17$. For example, if we have a point $(x_0,y_0)$, we check if $y_0=-x_0+17$.
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The x - intercept of $\overleftrightarrow{CD}$ is $17$. (The second part about the point that lies on $\overleftrightarrow{CD}$ is incomplete in the problem statement, but if we had options we would substitute values into $y=-x + 17$ to check).