Question

10 numeric 1 point if lm = 41 - 2x and np = 7x + 5, find lm. answer 33

Explanation:

Step1: Set LM equal to NP (chords of equal length)

Since \( LM \) and \( NP \) are chords of the same circle with equal markings (indicating they are equal in length), we set \( LM = NP \). So, \( 41 - 2x = 7x + 5 \).

Step2: Solve for x

Add \( 2x \) to both sides: \( 41 = 9x + 5 \).
Subtract 5 from both sides: \( 36 = 9x \).
Divide both sides by 9: \( x = 4 \).

Step3: Find LM

Substitute \( x = 4 \) into \( LM = 41 - 2x \):
\( LM = 41 - 2(4) = 41 - 8 = 33 \).

Answer:

33