Question

8 × 10⁵ is how many times as great as 8 × 10⁻¹? 10⁴ 10⁶ 10⁻⁶ 10⁻⁴

Explanation:

Step1: Set up the division

To find how many times \(8\times10^{5}\) is as great as \(8\times10^{-1}\), we divide \(8\times10^{5}\) by \(8\times10^{-1}\).

$$ \frac{8\times10^{5}}{8\times10^{-1}} $$

Step2: Simplify the coefficients and exponents

The 8 in the numerator and denominator cancels out. For the exponents, we use the rule \(\frac{10^{a}}{10^{b}} = 10^{a - b}\). So we have \(10^{5-(-1)}\).

$$ 10^{5 + 1}=10^{6} $$

Answer:

\(10^{6}\) (corresponding to the option with \(10^{6}\))