Question

10 formula 1 point determine the density of a regular solid with a mass of 249.2 g and dimensions of 5.7cm x 7.9cm x 9.7cm. round your answer to 2 decimal places. answer 11 formula 1 point a student wishes to determine the mass of an unknown solid. the mass of the solid is 10.2 g. the diagram shows the water level in the graduated cylinder before and after the solid was added. what is the density, in g/ml, of the unknown solid? express your answer with 2 decimal places. before solid is added after solid is added

Explanation:

Question 10

Step1: Calculate volume of the solid

The solid is a rectangular prism, so volume \( V = l \times w \times h \). Given \( l = 5.7\,\text{cm} \), \( w = 7.9\,\text{cm} \), \( h = 9.7\,\text{cm} \).
\( V = 5.7 \times 7.9 \times 9.7 \)
First, \( 5.7 \times 7.9 = 45.03 \), then \( 45.03 \times 9.7 = 436.791\,\text{cm}^3 \) (since \( 1\,\text{cm}^3 = 1\,\text{mL} \), volume is \( 436.791\,\text{mL} \)).

Step2: Calculate density

Density formula: \(
ho = \frac{m}{V} \), where \( m = 249.2\,\text{g} \), \( V = 436.791\,\text{mL} \).
\(
ho = \frac{249.2}{436.791} \approx 0.57\,\text{g/mL} \) (rounded to 2 decimal places).

Question 11

Step1: Find volume of the solid (displacement method)

Volume of solid = Volume after - Volume before. From the diagram, before: \( 7\,\text{mL} \), after: \( 20\,\text{mL} \).
\( V = 20 - 7 = 13\,\text{mL} \).

Step2: Calculate density

Density formula: \(
ho = \frac{m}{V} \), where \( m = 10.2\,\text{g} \), \( V = 13\,\text{mL} \).
\(
ho = \frac{10.2}{13} \approx 0.78\,\text{g/mL} \) (rounded to 2 decimal places).

Answer:

s:
Question 10: \( \boldsymbol{0.57}\,\text{g/mL} \)
Question 11: \( \boldsymbol{0.78}\,\text{g/mL} \)